If the vectors a and b are mutually perpendic | vedclass

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(C) Given that $a$ and $b$ are mutually perpendicular,so $a \cdot b = 0$.Using the vector triple product formula $a 	imes (b 	imes c) = (a \cdot c)b

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$|a|^4 b$

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(C) Given that $a$ and $b$ are mutually perpendicular,so $a \cdot b = 0$.Using the vector triple product formula $a 	imes (b 	imes c) = (a \cdot c)b - (a \cdot b)c$.First,evaluate $a 	imes (a 	imes b) = (a \cdot b)a - (a \cdot a)b = 0 - |a|^2 b = -|a|^2 b$.Next,evaluate $a 	imes \{ a 	imes (a 	imes b) \} = a 	imes (-|a|^2 b) = -|a|^2 (a 	imes b)$.Finally,evaluate $a 	imes \{ a 	imes \{ a 	imes (a 	imes b) \} \} = a 	imes (-|a|^2 (a 	imes b)) = -|a|^2 (a 	imes (a 	imes b))$.Substitute the result from the first step: $-|a|^2 (-|a|^2 b) = |a|^4 b$.

If the vectors $a$ and $b$ are mutually perpendicular,then $a \times \{ a \times \{ a \times (a \times b)\} \}$ is equal to

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